-23x^2+300x+2=0

Solution for -23x^2+300x+2=0 equation:

-23x^2+300x+2=0

a = -23; b = 300; c = +2;
Δ = b2-4ac
Δ = 3002-4·(-23)·2
Δ = 90184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{90184}=\sqrt{4*22546}=\sqrt{4}*\sqrt{22546}=2\sqrt{22546}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-2\sqrt{22546}}{2*-23}=\frac{-300-2\sqrt{22546}}{-46}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+2\sqrt{22546}}{2*-23}=\frac{-300+2\sqrt{22546}}{-46}
$